如图,已知A,B,C为不在同一直线上的三点,AA1∥BB1∥CC1,且AA1=BB1=CC
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/08/06 16:49:41
如图,已知A,B,C为不在同一直线上的三点,AA1∥BB1∥CC1,且AA1=BB1=CC
如图,已知A,B,C为不在同一直线上的三点,AA1∥BB1∥CC1,且AA1=BB1=CC1,
1.若AA1⊥平面ABC,且AC=AA1=4,BC=3,AB=5,求证:A1C⊥平面AB1C1
![](http://img.wesiedu.com/upload/d/15/d154f718142740ccbbb2485bcba18085.jpg)
如图,已知A,B,C为不在同一直线上的三点,AA1∥BB1∥CC1,且AA1=BB1=CC1,
1.若AA1⊥平面ABC,且AC=AA1=4,BC=3,AB=5,求证:A1C⊥平面AB1C1
![](http://img.wesiedu.com/upload/d/15/d154f718142740ccbbb2485bcba18085.jpg)
![如图,已知A,B,C为不在同一直线上的三点,AA1∥BB1∥CC1,且AA1=BB1=CC](/uploads/image/z/8567409-57-9.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5A%2CB%2CC%E4%B8%BA%E4%B8%8D%E5%9C%A8%E5%90%8C%E4%B8%80%E7%9B%B4%E7%BA%BF%E4%B8%8A%E7%9A%84%E4%B8%89%E7%82%B9%2CAA1%E2%88%A5BB1%E2%88%A5CC1%2C%E4%B8%94AA1%3DBB1%3DCC)
∵AA1⊥面ABC,BC在面ABC上
∴AA1⊥BC,
又∵BC=3,AC=4,AB=5,
∴BC⊥AC,
∵AA1和AC同在面AA1C1C上,
∴BC⊥面AA1C1C
∵A1C在面AA1C1C上,
∴BC⊥A1C,
∵BB1∥CC1且BB1=CC1,
∴BB1C1C是平行四边形,
∴BC∥B1C1,
∵BC⊥A1C,
∴B1C1⊥A1C,
又∵AC=AA1=A1C1=C1C,AA1⊥AC,
∴AA1C1C是正方形
∵AC1和A1C是两条对角线,
∴AC1⊥A1C,
∵AC1、B1C1同在面AB1C1上,A1C⊥AC1,A1C⊥B1C1,
∴A1C⊥面AB1C1,得证.
∴AA1⊥BC,
又∵BC=3,AC=4,AB=5,
∴BC⊥AC,
∵AA1和AC同在面AA1C1C上,
∴BC⊥面AA1C1C
∵A1C在面AA1C1C上,
∴BC⊥A1C,
∵BB1∥CC1且BB1=CC1,
∴BB1C1C是平行四边形,
∴BC∥B1C1,
∵BC⊥A1C,
∴B1C1⊥A1C,
又∵AC=AA1=A1C1=C1C,AA1⊥AC,
∴AA1C1C是正方形
∵AC1和A1C是两条对角线,
∴AC1⊥A1C,
∵AC1、B1C1同在面AB1C1上,A1C⊥AC1,A1C⊥B1C1,
∴A1C⊥面AB1C1,得证.
如图,已知A,B,C为不在同一直线上的三点,AA1∥BB1∥CC1,且AA1=BB1=CC
如图,已知A,B,C为不在同一直线上的三点,且AA1∥BB1∥CC1,AA1=BB1=CC1.
A,B,C为不在同一条直线上的三点,AA1平行BB1平行CC1,且AA1等于BB1等于CC1求证,平面ABC平行A1B1
如图,点P为斜三棱柱ABC-A1B1C1的侧棱BB1上一点,PM⊥BB1交AA1于点M,PN⊥BB1交CC1于点N.
如图已知三角形abc和三角形A1B1C1的对应顶点的连线AA1、BB1、CC1交于同一点O,且A1O分之AO=B1O分之
如图,已知正三棱柱ABC-A1B1C1的底面边长为2,侧棱长为32,点E在侧棱AA1上,点F在侧棱BB1上,且AE=22
如图,已知∠A=∠B,AA1,PP1,BB1均垂直于A1B1,AA1=17,PP1=16,BB1=20,A1B1=12,
如图,已知∠A=∠B,AA1,PP1,BB1均垂直于A1B1,AA1=17,PP1=16,BB1=20,A1B1=12则
伴你成长如图,由平行四边形ABCD的各顶点向直线l引垂足,分别为A1,B1,C1,D1,求证AA1+CC1=BB1+DD
立体几何基础已知几何形ABC-A1B1C1,AA1‖BB1‖CC1,AA1=2,BB1=2,CC1=3 设O为AB中点,
如图,A,B,C为不在同一条直线上的三点,AA'//BB'//CC',且AA'=BB'=CC'求证:平面ABC//平面A
如图:直三棱柱ABC-A1B1C1中,AC=BC=AA1=2,∠ACB=90°.E为BB1的中点,D点在AB上且DE=3