搜狗做题网线性代数的问题,应该不难,
来源：学生作业帮 编辑：搜狗做题网作业帮 分类：数学作业 时间：2024/07/05 04:00:14
线性代数的问题,应该不难,
For which values of "a" will be the following system have no solutions?Exactly one solution?Infinitely many solutions?
x + 2y - 3z =4
3 x - y + 5z =2
4 x + y + (a^2-14)z =a+4
上面是a+2不是a+4
For which values of "a" will be the following system have no solutions?Exactly one solution?Infinitely many solutions?
x + 2y - 3z =4
3 x - y + 5z =2
4 x + y + (a^2-14)z =a+4
上面是a+2不是a+4
将方程组的增广矩阵作初等行变换,分为梯矩阵:
1 2 -3 4
0 -7 14 -10
0 0 a^2-16 a-2
可知:当a=4 或 -4 时,方程组无解.
当a!=4 且 a!= -4 时,方程组有唯一解.
1 2 -3 4
0 -7 14 -10
0 0 a^2-16 a-2
可知:当a=4 或 -4 时,方程组无解.
当a!=4 且 a!= -4 时,方程组有唯一解.