计算:(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:综合作业 时间:2024/07/22 06:26:04
计算:(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004+1/2005)x(1/2003+1/2004)
![计算:(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004](/uploads/image/z/7897067-35-7.jpg?t=%E8%AE%A1%E7%AE%97%3A%282%2B1%2F2003%2B1%2F2004%29x%281%2F2003%2B1%2F2004%2B1%2F2005%29%E2%80%94%282%2B1%2F2003%2B1%2F2004)
设1/2003+1/2004=x
1/2003+1/2004+1/2005=y
(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004+1/2005)x(1/2003+1/2004)
=(2+x)y-(2+y)x
=2y+xy-2x-xy
=2y-2x
=2(y-x)
=2*1/2005
=2/2005
1/2003+1/2004+1/2005=y
(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004+1/2005)x(1/2003+1/2004)
=(2+x)y-(2+y)x
=2y+xy-2x-xy
=2y-2x
=2(y-x)
=2*1/2005
=2/2005
计算1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3).+1/(x+2003)(x+2004)
计算:(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004
计算3/x-2+2/1-x
计算(-2x+1)(-3x+5)
计算(2x+x-1)平方
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
计算 x(x+3)-(x-1)(x-2)
如何计算 (x+1)(x+2)(x+3)(x+4)
计算:(x+1)(x-2)(x-3)(x-6)
计算(X-1)(X-2)(X-3)(X-4)
计算:(1x
分式混合计算(x+1/x^2-x - x/x^2-2x+1)*x