cosπ/6+根号3sinπ/6=?
cosπ/6+根号3sinπ/6=?
求证 cos(A)+ 根号3sin(A)=2sin(π/6+A)
cos(π/6-x)=根号3/3则cos(5π/6+x)-sin(x-π/6)的平方
若tanθ=根号3/3,则cos^2θ-sin(θ+π/6)cosθ的值
已知cos(α-π/6)+sinα=4/5 根号3,则sin(α+7/6π)=?
已知cos(α-π/6)+sinα=(4倍根号3)/5,则sin(α+7π/6)=
已知sin(π/6-a)=根号3/3,则 cos(4π/3+a)
函数y=根号3/2sin(x+π/2)+cos(π/6-x)的最大值
根号3×cosπ/12-sinπ/12=?
已知cos(6/π-α)=三分之根号三,求证:sin(4π/3+α)+cos的平方(2π/3-α)=.(2-根号3)/3
1.化简根号2cos x - 根号6sin x2.已知sin(α-β)cosα-cos(β-α)sinα=3/5,β是第
已知cos(π\3-2)=1\3,则cosα+根号3sinα=