带根号的!1/(3+根号3)+1/(5根号3+3根号5)+1/(7根号5+5根号7)+...+1/(49根号47+47根
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/07/16 00:12:36
带根号的!
1/(3+根号3)+1/(5根号3+3根号5)+1/(7根号5+5根号7)+...+1/(49根号47+47根号49)
1/(3+根号3)+1/(5根号3+3根号5)+1/(7根号5+5根号7)+...+1/(49根号47+47根号49)
![带根号的!1/(3+根号3)+1/(5根号3+3根号5)+1/(7根号5+5根号7)+...+1/(49根号47+47根](/uploads/image/z/6715154-2-4.jpg?t=%E5%B8%A6%E6%A0%B9%E5%8F%B7%E7%9A%84%211%2F%EF%BC%883%2B%E6%A0%B9%E5%8F%B73%EF%BC%89%2B1%2F%EF%BC%885%E6%A0%B9%E5%8F%B73%2B3%E6%A0%B9%E5%8F%B75%EF%BC%89%2B1%2F%EF%BC%887%E6%A0%B9%E5%8F%B75%2B5%E6%A0%B9%E5%8F%B77%EF%BC%89%2B...%2B1%2F%EF%BC%8849%E6%A0%B9%E5%8F%B747%2B47%E6%A0%B9)
/>原式的通项公式为:
an = 1/[(n+2)根号n + n根号(n+2)]
=1/[根号{n(n+2)} * {根号(n+2) + 根号n}]
={根号(n+2) - 根号n}/[2根号{n(n+2)}]
=1/2 *[1/根号n - 1/根号(n+2)]
所以原式= 1/2 *[(1/1 - 1/根号3)+ (1/根号3 - 1/根号5) + (1/根号5 - 1/根号7) +...+(1/根号47 - 1/根号49)]
= 1/2 *(1 - 1/7)
= 1/2 * 6/7
= 3/7
an = 1/[(n+2)根号n + n根号(n+2)]
=1/[根号{n(n+2)} * {根号(n+2) + 根号n}]
={根号(n+2) - 根号n}/[2根号{n(n+2)}]
=1/2 *[1/根号n - 1/根号(n+2)]
所以原式= 1/2 *[(1/1 - 1/根号3)+ (1/根号3 - 1/根号5) + (1/根号5 - 1/根号7) +...+(1/根号47 - 1/根号49)]
= 1/2 *(1 - 1/7)
= 1/2 * 6/7
= 3/7
(根号1+根号2+根号3+根号4+根号5+根号6+根号7+根号8+根号9+根号10)÷2
带根号的!1/(3+根号3)+1/(5根号3+3根号5)+1/(7根号5+5根号7)+...+1/(49根号47+47根
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