sinθ=3×cosθ (sinθ)²=()×(cosθ)²
sinθ=3×cosθ (sinθ)²=()×(cosθ)²
已知tanθ=根号2,求(1)(cosθ+sinθ)/(cosθ-sinθ);(2)sin²θ-sinθcos
参数方程化为普通方程 x=(sinθ+cosθ)/(2sinθ+3cosθ) y=sinθ/(2sinθ+3cosθ)
2sinα=sinθ+cosθ,sin²β==sinθcosθ.求证cos2β=2cos2α=2cos
求证:(1+cosθ+cosθ/2) /(sinθ+sinθ/2)=sinθ/1-cosθ
求证(1+sinθ+cosθ)/(1+sinθ-cosθ)+(1-cosθ+sinθ)/(1+cosθ+sinθ)=2/
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos
已知tanθ=3,求4sin²θ-3sinθcosθ-5cos²θ=?
求证sinθ/(1+cosθ)+(1+cosθ)/sinθ=2/sinθ
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
sinθ-cosθ=1/2,则sin^3θ-cos^3θ=?.
已知sinθ+2cosθsinθ−cosθ=3,求值: