搜狗做题网高一数学(2+lg2+1)lg5+(2+lg2)lg2=?
高一数学(2+lg2+1)lg5+(2+lg2)lg2=?
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5
lg5*(1+lg2)+(lg2)^2=
2(lg2)2+lg2•lg5+(lg2)2-lg2+1=lg2（2lg
(lg2)^2+lg2*lg5+(lg5)^2=
2lg5*lg2=
=(lg5)^2+lg2×lg5+lg2 =lg5×(lg5+lg2)+lg2麻烦问一下,这是咋做的
1/2(lg2)^2+1/2lg2*lg5+√1/4(lg2)^2-lg2+1=?
lg5^2+2lg2-lg2^2=?
lg5+2lg2+（lg2）=?
lg^2 5+lg2*lg5+lg2=?
lg50+lg2*lg5+(lg2)^2=