(-5)x3/13+(-5)x(-2/13)-5X1/13+0.125x(-14/13)x(-8)
(-5)x3/13+(-5)x(-2/13)-5X1/13+0.125x(-14/13)x(-8)
求线性方程组一般解2x1+x^2-x3+x4=13x1-2x^3+x3-3x4=4x1+4x^2-3x3+5x4=-2
分解因式:-27x3+8 ,(x2-5x+2)(x2-5x+4)-24 ,x5+x4+x3+x2+x1+1
解方程(x3+7x2+x+30)/(x2+5x+13)=(2x3+11x2+36x+45)/(2x2+7x+20)
双曲线y^2/12-x^2/13=1的一支上有三个点A(x1,y1),B(x2,6)C(x3,y3)与焦点F(0,5)的
线性方程组求解 2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
方程(13x-x^2)/(x+1)与x+(13-x)/(x+1)的积为42,的解是( ) 答案是x1=1,x2=6,x3
几道线代题求一个正交变换x=py,将二次型f(x1,x2,x3)=5x1²+5x2²+2x3
线性代数 RT.已知二次型f(x1,x2,x3)=(X^T)AX=x1^2-5x2^2+x3^2+2ax1x2+2x1x
max z=5*x1+2*x2^2+x3^2 x1+4*x2+3*x3=6 x(i)>=0,i=1,2,3 用lingo
求一个正交变换x=Py,使二次型5(X1,X2,xX3)=2X1^2+3X3^2+4X2*X3化为标准型