分解因式(x+y+z)³+(3x-2y-3z)³-(4x-y-2x)³
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/08/16 15:02:17
分解因式(x+y+z)³+(3x-2y-3z)³-(4x-y-2x)³
两解,最好两解,
两解,最好两解,
![分解因式(x+y+z)³+(3x-2y-3z)³-(4x-y-2x)³](/uploads/image/z/2962595-11-5.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%88x%2By%2Bz%EF%BC%89%26%23179%3B%2B%EF%BC%883x-2y-3z%EF%BC%89%26%23179%3B-%EF%BC%884x-y-2x%EF%BC%89%26%23179%3B)
(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³
=(x+y+z)³+[(3x-2y-3z)-(4x-y-2z)][(3x-2y-3z)²+(3x-2y-3z)(4x-y-2z)+(4x-y-2z)²]
=(x+y+z)³-(x+y+z)[(3x-2y-3z)²+(3x-2y-3z)(4x-y-2z)+(4x-y-2z)²]
=(x+y+z)[(x+y+z)²-(3x-2y-3z)²-(3x-2y-3z)(4x-y-2z)-(4x-y-2z)²]
再问: 好像还能在分解。。。
=(x+y+z)³+[(3x-2y-3z)-(4x-y-2z)][(3x-2y-3z)²+(3x-2y-3z)(4x-y-2z)+(4x-y-2z)²]
=(x+y+z)³-(x+y+z)[(3x-2y-3z)²+(3x-2y-3z)(4x-y-2z)+(4x-y-2z)²]
=(x+y+z)[(x+y+z)²-(3x-2y-3z)²-(3x-2y-3z)(4x-y-2z)-(4x-y-2z)²]
再问: 好像还能在分解。。。
(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³分解因式
分解因式(x+y+z)³+(3x-2y-3z)³-(4x-y-2x)³
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