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来源：学生作业帮编辑：搜狗做题网作业帮分类：数学作业时间：2024/07/13 02:50:05

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四个数成递增等差数列,中间两数的和为2,首末两项的积为-8,求这4个数.

设首项为a公差为d 则a1=a,a2=a+d,a3=a+2d,a4=a+3d
由已知中间两数的和为2可知a+d+a+2d=2-----------1
又由已知首末两项的积为-8可知a(a+3d)=-8---------2
联立1,2可解得排除递减的情况可知四个数为-2,0,2,4

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