已知x+y=4,xy=5,求2x²+2y²+5xy的值
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已知x+y=4,xy=5,求2x²+2y²+5xy的值
已知a+b=3,ab=-12.求(a-1)(b-1)的值;a²+b²的值;(a-b)²的值.
急
已知a+b=3,ab=-12.求(a-1)(b-1)的值;a²+b²的值;(a-b)²的值.
急
![已知x+y=4,xy=5,求2x²+2y²+5xy的值](/uploads/image/z/2463632-8-2.jpg?t=%E5%B7%B2%E7%9F%A5x%2By%3D4%2Cxy%3D5%2C%E6%B1%822x%26%23178%3B%2B2y%26%23178%3B%2B5xy%E7%9A%84%E5%80%BC)
2x²+2y²+5xy
=2(x+y)²+xy
=2*4^2+5
=32+5
=37
(a-1)(b-1)
=ab-a-b+1
=-12-3+1
=-14
a²+b²
=(a+b)²-2ab
=3²+2*12
=33
(a-b)²
=a²+b²-2ab
=33+2*12
=57
再问: �Ǹ�������ab=-12.
再答: ��֪��
再问: ����һ�⡣��֪x²-y²=4��x+y=8 ��3x-3y��ֵ
再答: 不回答追问里的新问题,请采纳了再提问,谢谢!
=2(x+y)²+xy
=2*4^2+5
=32+5
=37
(a-1)(b-1)
=ab-a-b+1
=-12-3+1
=-14
a²+b²
=(a+b)²-2ab
=3²+2*12
=33
(a-b)²
=a²+b²-2ab
=33+2*12
=57
再问: �Ǹ�������ab=-12.
再答: ��֪��
再问: ����һ�⡣��֪x²-y²=4��x+y=8 ��3x-3y��ֵ
再答: 不回答追问里的新问题,请采纳了再提问,谢谢!
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