设sin(x+y)sin(x-y)=m,则cos^2x-cos^2y的值
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设sin(x+y)sin(x-y)=m,则cos^2x-cos^2y的值
![设sin(x+y)sin(x-y)=m,则cos^2x-cos^2y的值](/uploads/image/z/2015308-28-8.jpg?t=%E8%AE%BEsin%28x%2By%29sin%28x-y%29%3Dm%2C%E5%88%99cos%5E2x-cos%5E2y%E7%9A%84%E5%80%BC)
sin(x+y)sin(x-y)=[sinxcosy+sinycosx][sinxcosy-cosxsiny]=(sinxcosy)^2-(cosxsiny)^2
=(1-cos^2y)cos^2y-cos^2x(1-cos^2y)
=cos^2y-cos^2x=m
故cos^2x-cos^2y=-m
再问: (sinxcosy)^2-(cosxsiny)^2怎么到 (1-cos^2y)cos^2y-cos^2x(1-cos^2y)
再答: (sinxcosy)^2-(cosxsiny)^2 =sin^2xcos^2y-cos^2xsin^2y 不好意思 我(1-cos^2y)那里写错了 应该是(1-cos^2x) 如下 =(1-cos^2x)cos^2y-cos^2x(1-cos^2y) =cos^2y-cos^2x
=(1-cos^2y)cos^2y-cos^2x(1-cos^2y)
=cos^2y-cos^2x=m
故cos^2x-cos^2y=-m
再问: (sinxcosy)^2-(cosxsiny)^2怎么到 (1-cos^2y)cos^2y-cos^2x(1-cos^2y)
再答: (sinxcosy)^2-(cosxsiny)^2 =sin^2xcos^2y-cos^2xsin^2y 不好意思 我(1-cos^2y)那里写错了 应该是(1-cos^2x) 如下 =(1-cos^2x)cos^2y-cos^2x(1-cos^2y) =cos^2y-cos^2x
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