1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,(
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1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,( A.140 B.144 C.44 D.463.1,8,9,4,(),1/6 A.3 B.2 C.1 D.1/34.1,1,5,-3,10,-8,( A.-4 B.-10 C.14 D.165.某仪仗队排成方阵,第一次排列若干人,结果多余100人;第二次比第一次增加3人,又少29人,仪仗队总人数为多少? A.400 B.450 C.500 D.600
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第1题,奇数项各+1,偶数项各-1后得新数列:1,8 ,27 ,64 ,125 ,216这个分别是16的立方.因此,()=216+1=217 答案选D第2题,分组看(19,76);(28,112);(36,后1项都是前一项的4倍,于是,=144 答案选B第3题,1=1^4 8=2^3 9=3^2 4=4^1 1=5^0 1/6=6^(-1因此答案选C第4题,分奇数,偶数项来看,奇数项:1 ,5 ,10 ,偶数项:1,-3,-8,可见,奇数项的两两差分别是4,5.递增 而偶数项的两两差分别是-4,-5.递减于是,=10+6=16 答案选D第5题,设第1次方阵的边长是X,则第2次的边长是X+3,依题意得:X^2+100=(X+3)^2-29这样解得:X=20于是,仪仗队总人数是:20^2+100=500答案选C
1.0,9,26,65,124,( A.186 B.215 C.216 D.2172.19,76,28,112,36,(
0,9,26,65,124,(A.186 B.215 C.216 D.21734,36,35,35,(),34,37(A
0,9,26,65,124,( )A.186 B.217 C.216 D.215本人资质有限,算了好久仍是一头雾水,
0,9,26,65,124,( ) A.165 B.193 C.217 D.239
2,9,28,65,() A、128 B、124 C、126 D、129
[a,b)×[c,d
a,b ,c ,d
23 11 6884 9 186A.125 B.216 C.218 D.25617 42 710 124 79 13A.
A B C D × 9 ___________________ D C B A (1) A = ( )(2) B = (
A B C D * 9 = D C B A ,请问A B C D各代表什么数字?
( )-(c-d)=(a-c)-(-b+d)
a b c d × 9 _____________