y=【(2x+1)(2-3x)^1/3】/(x-3)^2/3求导
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y=【(2x+1)(2-3x)^1/3】/(x-3)^2/3求导
![y=【(2x+1)(2-3x)^1/3】/(x-3)^2/3求导](/uploads/image/z/11562096-48-6.jpg?t=y%3D%E3%80%90%282x%2B1%29%EF%BC%882-3x%EF%BC%89%5E1%2F3%E3%80%91%2F%28x-3%29%5E2%2F3%E6%B1%82%E5%AF%BC)
y=(2x+1)(2-3x)^(1/3)(x-3)^(-2/3)
y'=(2x+1)'*(2-3x)^(1/3)(x-3)^(-2/3)+(2x+1)[(2-3x)^(1/3)]'(x-3)^(-2/3)+(2x+1)(2-3x)^(1/3)[(x-3)^(-2/3)]'
=2(2-3x)^(1/3)(x-3)^(-2/3)+1/3*(-3)*(2x+1)(2-3x)^(-2/3)(x-3)^(-2/3)-(2/3)(2x+1)(2-3x)^(1/3)(x-3)^(-5/3)
=2(2-3x)^(1/3)(x-3)^(-2/3)-(2x+1)(2-3x)^(-2/3)(x-3)^(-2/3)-(2/3)(2x+1)(2-3x)^(1/3)(x-3)^(-5/3)
y'=(2x+1)'*(2-3x)^(1/3)(x-3)^(-2/3)+(2x+1)[(2-3x)^(1/3)]'(x-3)^(-2/3)+(2x+1)(2-3x)^(1/3)[(x-3)^(-2/3)]'
=2(2-3x)^(1/3)(x-3)^(-2/3)+1/3*(-3)*(2x+1)(2-3x)^(-2/3)(x-3)^(-2/3)-(2/3)(2x+1)(2-3x)^(1/3)(x-3)^(-5/3)
=2(2-3x)^(1/3)(x-3)^(-2/3)-(2x+1)(2-3x)^(-2/3)(x-3)^(-2/3)-(2/3)(2x+1)(2-3x)^(1/3)(x-3)^(-5/3)