(9/4)^(-1/2)+log8 9*log3 32=
(9/4)^(-1/2)+log8 9*log3 32=
log3(2)*log8(9)
计算log8底9*log3底32
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
log8 9乘log3 4等于几?求解 多谢
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
log3(2)*log8(9)怎么计算?
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
(log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9)
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)