a方 6a 9分之81-a方
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因为a/b=3所以a=3b所以(a方+ab+b方)/(a方+b方)=(9b方+3b方+b方)/(9b方+b方)(说明:将a=3b带入)=13b方/10b方=13/10
5X/25x^2=1/5x,(9ab^2+6abc)/3a^2b=3ab(3b+2c)/3a^2b=(3b+2c)/a(9a^2+6ab+b^2)/(3a+b)=(3a+b)^2/(3a+b)=3a+
原式=[(a+b)(a-b)/a(a-b)]÷[(a²+2ab+b²)/a]=[(a+b)/a]×[a/(a+b)²]=1/(a+b)b=-1假设a=2原式=1/(2-1
-(-b分之a二次方)二次方×(-a分之b三次方)三次方÷(ab)四次方=a的4次方/b²x-b的9次方/a³÷(a的4次方b的4次方)=-b的7次方a÷(a的4次方b的4次方)=
解√(a²-b²)/(a+b)=√(a-b)(a+b)/(a+b)=√(a-b)再问:����再答:���ǡ�(a²-b²)/(a+b)�ɣ��Ǿ������Ǹ
(a²-9)/(a²+6a+9)+(a-3)/(a+3)-(a-a²)/(a²+2a-3)=[(a+3)(a-3)]/(a+3)²+(a-3)/(a+
再答:题目是这样的么再答:再问:不是再答:照相给我再问:再答:就是这样的啊再答:没错
a/b=2,a=2b.(a^2-ab+3b^)/(a^2+ab+6b^)=(4b^2-2b^2+3b^)/(4b^2+2b^2+6b^)=5b^2/(12b^2)=5/12
a²+2a+1=(a+1)²所以最简公分母是a²(a+1)²所以(a-1)/(a²+2a+1)=a²(a-1)/[a²(a+1)&
[(81-a²)/(a²+6a+9)]÷[(9-a)/(2a+6)]×[1/(a+9)]=[(81-a²)(2a+6)]/[(a²+6a+9)(9-a)(a+9
化简(4a+3b)(a-2b)分之(a-b)(a-2b)除以(a-2b)分之2a(a-b)=2a(4a+3b)分之(a-2b)代入数就自己做吧(*^_^*)
化简出来应该是ab(a²-1).很简单,因为a-4的绝对值为非负数,根号B-9也为非负数,所以两个个非负数之和等于0,两数必为0所以b为9,a等于4.带入就是36乘以15等于540.
a方+2a+1分之a方-1-a方分之a方+2a=a²/(a+1)²+a(a+1)/(a²-1)=a²/(a+1)²+a(a+1)/(a+1)(a-1)
(3b²/4a²)x(-a/6b)=-3ab²/(4a²x6b)=-b/(8a)(8a分之负b)
由(a^-8a+16)+(b^+6b+9)=0(a-4)^+(b+3)^=0得a=4,b=-3将数值代入(a^+ab-6^)/(a^-4ab+4b^)得(-32)/(a-2b)^(-32)/100=-
因为A^2+B^2-8A+6B+25=0,所以(A^2-8A+16)+(B^2+6B+9)=0,所以(A-4)^2+(B+3)^2=0,所以A-4=0,B+3=0,所以A=4,B=-3,所以(A^2+
a/b=2a=2b(a^2-ab+b^2)/(a^2+b^2)=(4b^2-2b^2+b^2)/(4b^2+b^2)=3/5
a/b=2分式分子分母同除以b²(a²-ab+3b²)/(a²+ab+6b²)=[(a/b)²-(a/b)+3]/[(a/b)²+
(0.25a^2b-0.5a^3b^2-1/6a^4b^3)÷0.5a^2b=0.5-ab-1/3a^2b^2