搜狗做题网计算:(1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1+1/2^2)(1+1/2) .
来源：学生作业帮 编辑：搜狗做题网作业帮 分类：数学作业 时间：2024/07/13 16:44:06
计算:(1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1+1/2^2)(1+1/2) .
原式=:〔(1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1+1/2^2)(1+1/2)（1-1/2）〕/（1-1/2）
= [（1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1+1/2^2)(1-1/2^2)]/(1-1/2)
=[（1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1-1/2^4)]/(1-1/2)
=[（1+1/2^32)(1+1/2^16)(1+1/6^8)(1-1/2^8)]/(1-1/2)
=[（1+1/2^32)(1+1/2^16)(1-1/6^16)]/(1-1/2)
=[（1+1/2^32)(1-1/2^32)]/(1-1/2)
=（1-1/2^64)/(1/2)
=2-2/2^64
=2-1/2^63
= [（1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1+1/2^2)(1-1/2^2)]/(1-1/2)
=[（1+1/2^32)(1+1/2^16)(1+1/6^8)(1+1/2^4)(1-1/2^4)]/(1-1/2)
=[（1+1/2^32)(1+1/2^16)(1+1/6^8)(1-1/2^8)]/(1-1/2)
=[（1+1/2^32)(1+1/2^16)(1-1/6^16)]/(1-1/2)
=[（1+1/2^32)(1-1/2^32)]/(1-1/2)
=（1-1/2^64)/(1/2)
=2-2/2^64
=2-1/2^63