已知x-y=3,xy = -2,求代数式(2x=3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)的值
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已知x-y=3,xy = -2,求代数式(2x=3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)的值
![已知x-y=3,xy = -2,求代数式(2x=3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)的值](/uploads/image/z/2846263-31-3.jpg?t=%E5%B7%B2%E7%9F%A5x-y%3D3%2Cxy+%3D+-2%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%882x%3D3y-2xy%EF%BC%89-%28x%2B4y%2Bxy%29-%283xy%2B2y-2x-3%29%E7%9A%84%E5%80%BC)
题有问题
(2x=3y-2xy)怎么会是2X=?
原题:
(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)
(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)
=2x+3y-2xy-x-4y-xy-(3xy+2y-2x-3)
=x-y-3xy-(3xy+2y-2x-3)
=(x-y)-3xy-【3xy-2(x-y)-3】
=(x-y)-3xy-3xy+2(x-y)+3
=(x-y)-6xy+2(x-y)+3
=3(x-y)-6xy+3
=9+12+3
=24
(2x=3y-2xy)怎么会是2X=?
原题:
(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)
(2x+3y-2xy)-(x+4y+xy)-(3xy+2y-2x-3)
=2x+3y-2xy-x-4y-xy-(3xy+2y-2x-3)
=x-y-3xy-(3xy+2y-2x-3)
=(x-y)-3xy-【3xy-2(x-y)-3】
=(x-y)-3xy-3xy+2(x-y)+3
=(x-y)-6xy+2(x-y)+3
=3(x-y)-6xy+3
=9+12+3
=24
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