2-sin∧2(2x)=1+cos∧2(2x)这是怎么换算过去的?
数学三角函数换算sin 2x = cos 2x = 等等换算公式
已知(1+sin x)/cos x=1/2,则cos x/(sin x-1)的值是
cos^2 x - sin^2 x 是怎么化简=cos 2x
lim(sin(x^2*cos(1/x)))/x怎么做?
(sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x?
证明COS(X+Y)COS(X-Y)=COS^2X-SIN^2Y
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
三角函数(sin (x/2))/(cos(x/2))=(2sin^2(x/2))/(sinx)是怎么得来的,求详解
化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x
函数y=sin^2x+sin x cos x的值域是?
证明下列恒等式: (1)2sin(2/π+x)cos(2/π-x)*cosθ+(2cos^2x-1)*sinθ=sin(
2cos x (sin x -cos x)+1