求下列函数的Z反变换X(z)=1/(z+1)(z+2)
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求下列函数的Z反变换
X(z)=1/(z+1)(z+2)
X(z)=1/(z+1)(z+2)
![求下列函数的Z反变换X(z)=1/(z+1)(z+2)](/uploads/image/z/19985159-47-9.jpg?t=%E6%B1%82%E4%B8%8B%E5%88%97%E5%87%BD%E6%95%B0%E7%9A%84Z%E5%8F%8D%E5%8F%98%E6%8D%A2X%28z%29%3D1%2F%28z%2B1%29%28z%2B2%29)
1/(z+1)(z+2)=1/(z+1)-1/(z+2)
z/(z+1)(z+2)=z/(z+1)-z/(z+2)
(1)if the region is |z|>2
both terms are causal
the signal is (-(-1)^n+2(-2)^n)*u(n+1)
(2)if the region is 2>|z|>1
the first is causal and the second is anticausal
the signal is -(-1)^nu(n+1)-2*(-2)^n*u(-n-2)
(3)if the region is |z|
z/(z+1)(z+2)=z/(z+1)-z/(z+2)
(1)if the region is |z|>2
both terms are causal
the signal is (-(-1)^n+2(-2)^n)*u(n+1)
(2)if the region is 2>|z|>1
the first is causal and the second is anticausal
the signal is -(-1)^nu(n+1)-2*(-2)^n*u(-n-2)
(3)if the region is |z|
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