1/(1+y²/x²)×(y'x-y)/x²怎么化简成xy'-y
因式分解(xy-1)²+(x+y-2)(x+y-2y)怎么做哇?
x²/xy-x/y
已知x+y=1,xy=-二分之一,求x(x+y)(x-y)-x(x+y)²
【(1)/(x-y)+(1)/(x-y)】÷(2x)/(x²-2xy+y²)
计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
计算:1、(xy分之x²-y²)×(x-y分之x)-(y分之x);
x²+xy/(x-4y)(x+y),其中x=4,y=-1
计算:(xy-x²)×x-y/xy
xy-1+x-y
已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
(x+y)(x²-xy+y²)—xy(x+y)因式分解