(2m+n)²(2m-n)²等于?
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
设m等于1/5n求 2n/(m+2n)+m/(2n-m)+4mn/(4n²-m²)
化简m/(m+n)²+n/m²-n²-2n²/(m+n)(m²-n
(m+2n)²+2(m+n)(2m-n)+(2m+n)² 因式分解
m-n分之m - m+n分之n + m²-n²分之2mn
证明(m+n)²/2+(m+n)/4≥(m√n)+(n√m)
计算m-n+[(2n²)/(m+n)]
化简(m²/m-n - m+n)÷2m²-mn/n - m
【(m+n)(m-n)-(m-n²)+2n(m-n)】÷4n
设m=1/5n 设m等于1/5n求 2n/(m+2n)+m/(2n-m)+4mn/(4n²-m²)
m²+2mn+n²分之m²-n²等于多少?
(m²-2m)²n+2n(m²-2m)+n