化简:1+sina+cosa+2sinacosa/1+sina+cosa
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/08/05 09:27:34
化简:1+sina+cosa+2sinacosa/1+sina+cosa
![化简:1+sina+cosa+2sinacosa/1+sina+cosa](/uploads/image/z/19274578-34-8.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9A1%2Bsina%2Bcosa%2B2sinacosa%2F1%2Bsina%2Bcosa)
(1+sina+cosa+2sinacosa)/(1+sina+cosa)
=[﹙sin²a+cos²a+2sinacosa﹚+sina+cosa]/(1+sina+cosa)
=[(sina+cosa)²+1×(sina+cosa)]/(1+sina+cosa)
=(sina+cosa+1)(sina+cosa)/(1+sina+cosa)
=sina+cosa
再问: (sina+cosa+1)是怎么来的哇
再答: ﹙sin²a+cos²a+2sinacosa﹚+sina+cosa =(sina+cosa)²+sina+cosa =(sina+cosa)×(sina+cosa)+1×(sina+cosa)分解因式提取公因子(sina+cosa) =(sina+cosa+1)(sina+cosa)
=[﹙sin²a+cos²a+2sinacosa﹚+sina+cosa]/(1+sina+cosa)
=[(sina+cosa)²+1×(sina+cosa)]/(1+sina+cosa)
=(sina+cosa+1)(sina+cosa)/(1+sina+cosa)
=sina+cosa
再问: (sina+cosa+1)是怎么来的哇
再答: ﹙sin²a+cos²a+2sinacosa﹚+sina+cosa =(sina+cosa)²+sina+cosa =(sina+cosa)×(sina+cosa)+1×(sina+cosa)分解因式提取公因子(sina+cosa) =(sina+cosa+1)(sina+cosa)
证明1+sina+cosa+2sinacosa/1+sina+cosa=sina+cosa,
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