lim (sin nx)/x (x趋向0) =
极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-
设f(x)在0到正无穷大上可导,f(x)>0,limf(x)=1(x趋向正无穷大),若lim[f(x+nx)/f(x)]
lim(x趋向0)ln(1+sin x)/x^2
lim(x趋向正无穷)[x]*sin(1\x)=?
lim(x趋向于正无穷)(x*sin(1/x))=0 怎么用定义证明?
亲们,请问lim sin(1/x)/(1/x)= x趋向于0
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
lim(sin=√x²+1-sinx)当x趋向0是极限
Lim(x趋向0)xcotx=?
求极限(x趋向于0时)lim[sinx-sin(sinx)]/(sinx)^3
x趋向0 lim xcotx
lim[sin(xy)/xy],x趋向2,y趋向0,求极限