计算:(1)tan45°+sin230°-cos30°•tan60°+cos245°;(2)64−|−3|−3(3−π)
计算:(1)根号2sin45°+cos²60°-根号3tan60°+sin30°·tan45°
三角函数计算题1)2sin260°-√3tan30°-2cos245°2)√2×sin45°+√3×cos30°-3/2
根号【cos45°-cos30°】*2-tan60°分之tan45°+sin45°
(2009•黄浦区二模)计算:[2tan60°+1+(π−3)
tan30° sin30° cos30° tan60° sin60° cos60° tan45°
sin60 sin30 cos60 cos30 sin45 cos45 tan30 tan60 tan45°各等于多少
(2013•温州二模)(1)计算:(π−2)0+2cos30°−|−3|
数学题sin30°+ cos30°- tan45°
(2012•广陵区二模)(1)计算:27−2cos30°+(12)−2−|1−3|
计算tan60°+2sin45°-2cos30°的结果是______.
告诉下数学题sin30° cos30°- tan45° 要用呀,十分感谢各位朋友了3j
(1)sin60°-tan45°; (2)cos60°+tan60°; (3)根号2 /2 sin45°+sin60°-