{x+y/2 + x-y/2=6,4(x+y) - 5(x-y)=2 用换元法
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{x+y/2 + x-y/2=6,4(x+y) - 5(x-y)=2 用换元法
![{x+y/2 + x-y/2=6,4(x+y) - 5(x-y)=2 用换元法](/uploads/image/z/19043403-51-3.jpg?t=%EF%BD%9Bx%2By%2F2+%2B+x-y%2F2%3D6%2C4%EF%BC%88x%2By%29+-+5%28x-y%29%3D2+%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95)
用换元法,
设x+y=s,x-y=t,
则原方程组为,
s/2+t/3=6,①
4s-5t=2,②
将①×15+②,得,
23s/2=92
解得s=8,
t=6
即x+y=8,
x-y=6
两式加,得,x=7,y=1
所以方程组的解为
x=7
y=1
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再问: 验证过是错的
再答: 设:x+y=m,x-y=n
则原方程化为:m/2+n/2=6,4m+5n=2
解得,m=58,n=-46
所以,x+y=58,x-y=-46
解得,x=6,y=52
再问: 4m+5n应该是减吧
再答: 设:x+y=m,x-y=n
则原方程化为:m/2+n/2=6,4m-5n=2
解得,m=62/9,n=46/9
所以
x+y=62/9,x-y=46/9
x=6,y=8/9
设x+y=s,x-y=t,
则原方程组为,
s/2+t/3=6,①
4s-5t=2,②
将①×15+②,得,
23s/2=92
解得s=8,
t=6
即x+y=8,
x-y=6
两式加,得,x=7,y=1
所以方程组的解为
x=7
y=1
很高兴为您解答,【华工王师】团队为您答题.
请点击下面的【选为满意回答】按钮.
再问: 验证过是错的
再答: 设:x+y=m,x-y=n
则原方程化为:m/2+n/2=6,4m+5n=2
解得,m=58,n=-46
所以,x+y=58,x-y=-46
解得,x=6,y=52
再问: 4m+5n应该是减吧
再答: 设:x+y=m,x-y=n
则原方程化为:m/2+n/2=6,4m-5n=2
解得,m=62/9,n=46/9
所以
x+y=62/9,x-y=46/9
x=6,y=8/9
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