用夹逼法证明limx→∞[n/√(n^2+1)+n/√(n^2+2)+……+n/√(n^2+n)]=1
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
请问如何证明lim(n→∞)[n/(n2+n)+n/(n2+2n)+…+n/(n2+nn)]=1,
用数学归纳法证明:1×2×3+2×3×4+…+n×(n+1)×(n+2)=n(n+1)(n+2)(n+3)4(n∈N
limn→∞n√(1+1/n)(1+2/n)...(1+n/n)等于多少?
证明不等式:(1/n)的n次方+(2/n)的n次方+……+(n/n)的n次方
2^n/n*(n+1)
数学不等式证明题n=1,2,……证明:(1/n)^n+(1/2)^n+……+(n/n)^n第二个是(2/n)^n
证明1/(n+1)+1/(n+2)+1/(n+3)+……+1/(n+n)
limx-∞1+2+……+n/(n+3)(n+4)的极限要过程快
(1/(n^2 n 1 ) 2/(n^2 n 2) 3/(n^2 n 3) ……n/(n^2 n n)) 当N越于无穷大
求极限limx→∞[1^2/(n^3+1)+2^2/(n^3+2)+……+n^2/(n^3+n)]
证明C(0,n)^2+C(1,n)^2+……+C(n,n)^2=C(n,2n)