已知tanx=2,则tan(π4+2x)
已知 tanx=2,则tan(2(x-π/4))等于
已知X属于[-π/3,π/4]求函数y=tan平方X +2tanx
tanx+tan(π/2 -x)=?
证明sec x+tanx=tan(π/4 +x/2)
证明tanx+1/cosx=tan(x/2+π/4)
1)tan(x/2+π/4)+tan(x/2-π/4)=2tanx
tan(X/2+π/4)+tan(x/2-π/4)=2tanx?
tan( x/2+π/4)+tan(x/2-π/4 )=2tanx
tan(x/2+ π4)+tan(x/2- π/4)=2tanx
已知2tanx/(1+tan^2x)=3/5,求sin^2(π/4+x)的值
若tanx=2,则tan(π/4+2x)=?
tan(x/2)=2.求tanx