(x-y+z)( )=z²-(x-y)²,问括号内填?
①(x+y+z)(-x+y+z)(x-y+z)(x+y-z)
x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0),求x+y+z分之x+y-z
z=ln(x-2y)求二阶偏导数.
4x-3y-6z=0,x+2y-7z=0,xyz的积不等于0,求(x+y-z)/(x-y+2z)的值
已知×=负二分之一y=负三分之一z=六分之一求19(x-y+z)的平方减﹣24(x-y-z﹚减112﹙x-y+z﹚的值
x-〈-(y+z)〉去括号
已知方程组{2x-y+z=3,3x+4y-z=8,x+y-2z=-3若消去z得到二元一次方程组(),若消去y,得到二元
(x-y+z)(x+y+z)等于多少.
(x+y+z)*(-x+y+z)*(x-y+z)*(x+y-z)=
计算:(x+y+z)(-x+y+z)(x-y+z)(x+y-z).
因式分解:4x(x+y-z)+10a的平方(z-x-y)
已知有理数x,y,z,且|x-3|+2|y+1|+(2z+1)²=0,求x+y+z的相反数的倒数.