附加题:(y-z)2+(x-y)2+(z-x)2=(y+z-2x)2+(z+x-2y)2+(x+y-2z)2.
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附加题:(y-z)2+(x-y)2+(z-x)2=(y+z-2x)2+(z+x-2y)2+(x+y-2z)2.
求
求
(yz+1)(zx+1)(xy+1) |
(x
![]() ∵(y-z)2+(x-y)2+(z-x)2=(y+z-2x)2+(z+x-2y)2+(x+y-2z)2.
∴(y-z)2-(y+z-2x)2+(x-y)2-(x+y-2z)2+(z-x)2-(z+x-2y)2=0, ∴(y-z+y+z-2x)(y-z-y-z+2x)+(x-y+x+y-2z)(x-y-x-y+2z)+(z-x+z+x-2y)(z-x-z-x+2y)=0, ∴x2+y2+z2-2xy-2xz-2yz=0, ∴(x-y)2+(x-z)2+(y-z)2=0. ∵x,y,z均为实数, ∴x=y=z. ∴ (yz+1)(zx+1)(xy+1) (x2+1)(y2+1)(z2+1)= (x2+1)(y2+1)(z2+1) (x2+1)(y2+1)(z2+1)=1.
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