(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
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(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
=(m-n)(p-q)(p+2q)+(m-n)(p+q)(p+2q)
=(m-n)[(p-q)(p+2q)+(p+q)(p+2q)]
=(m-n)(p+2q)[(p-q)+(p+q)]
=(m-n)(p+2q)(2p)
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
=(p+2q)[(m-n)(p-q)-(n-m)(p+q)]
=(p+2q)[(mp-np-mq+nq)-(np-mp+nq-mq)]
=(p+2q)[mp-np-mq+nq-np+mp-nq+mq]
=(p+2q)[2mp-2np]
=(p+2q)[m-n](2p)
=(m-n)(p-q)(p+2q)+(m-n)(p+q)(p+2q)
=(m-n)[(p-q)(p+2q)+(p+q)(p+2q)]
=(m-n)(p+2q)[(p-q)+(p+q)]
=(m-n)(p+2q)(2p)
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
=(p+2q)[(m-n)(p-q)-(n-m)(p+q)]
=(p+2q)[(mp-np-mq+nq)-(np-mp+nq-mq)]
=(p+2q)[mp-np-mq+nq-np+mp-nq+mq]
=(p+2q)[2mp-2np]
=(p+2q)[m-n](2p)
(m+n+p-q)(m-n-p-q) 怎么算
(m+n)(p+q)-(m+n)(p-q)=
(m+n)^2-2(m+n)(p+q)-15(p+q)的解题过程
a(m-n)^p*(n-m)^q*(m-n)^q*(n-m)^p等于什么?
(p+2q)(2p-q)-(p+q)(p-q)
去括号:(m-n)(p-q)
因式分解:m(m-n)(p-q)-n(n-m)(p-q).
m的平方(P-q)-p+q
分解因式:(1)6p(p+q)-4q(p+q) (2)2ab(m-2n)4b(2n-m)
我要问问一道数学题M/N=Q/P=2/3 M+P/N+Q=?
若M=12p+3q,N=-3q-5p则M-2N=?
(m+n)(p-q)-(m+n)(q+p)