二分法的问题#include #include #include #define MIN 0.001double f (

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二分法的问题
#include
#include
#include
#define MIN 0.001
double f (double a,double b){
double c;
c = (sin(a) - a*a/4) * (sin(b) - b*b/4);
printf (" c is :%lf\n",c);
return c;
}
double erfen( double a ,double b){
double n;
n = a - b;
printf (" n is :%lf\n",n);
if (fabs(n)

if (f(mid ,b) < 0)
return erfen(mid,b);
else
return erfen(a,mid);

#include #include #include #include #include /* define 英语翻译#include #include #include #include #define WIN_CONSOLE #include#include#include#includeusing namespace std;#define #include #include #include #include #include #include #include #include#include#include#define LEN sizeof(struct LinkList)s #include #include #define TRUE 1 #define FALSE 0 #define OK #include #include #include #include< >和#include“ ”的区别 C语言：二分法#include#define f(x) (x*x*x-2*x*x+3*x-4)void main(){ ds18b20测温#include#include#define uchar unsigned char#define 英语翻译#include#include#define uchar unsigned char#define uint