若(2x-3)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5,则a1+2a2+3a3+4a4+5a5
来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/08/11 06:56:27
若(2x-3)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5,则a1+2a2+3a3+4a4+5a5=?
若(1+2x)^4=a0+a1x+a2x^2+a3x^3+a4x^4,则a1-2a2+3a3-4a4=?
若(1+2x)^4=a0+a1x+a2x^2+a3x^3+a4x^4,则a1-2a2+3a3-4a4=?
![若(2x-3)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5,则a1+2a2+3a3+4a4+5a5](/uploads/image/z/18035074-10-4.jpg?t=%E8%8B%A5%EF%BC%882x-3%EF%BC%89%5E5%3Da0%2Ba1x%2Ba2x%5E2%2Ba3x%5E3%2Ba4x%5E4%2Ba5x%5E5%2C%E5%88%99a1%2B2a2%2B3a3%2B4a4%2B5a5)
分别求导数
再分别赋值1,-1
即 ((2x-3)^5)'=(a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5)'
10(2x-3)^4= a1+2a2x+3a3x^2+4a4x^3+5a5x^4
赋值 x=1,则a1+2a2+3a3+4a4+5a5 = 10
((1+2x)^4)'=(a0+a1x+a2x^2+a3x^3+a4x^4)',
8(1+2x)^3= a1+2a2x+3a3x^2+4a4x^3,
赋值 x = -1,则a1-2a2+3a3-4a4= -8
再分别赋值1,-1
即 ((2x-3)^5)'=(a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5)'
10(2x-3)^4= a1+2a2x+3a3x^2+4a4x^3+5a5x^4
赋值 x=1,则a1+2a2+3a3+4a4+5a5 = 10
((1+2x)^4)'=(a0+a1x+a2x^2+a3x^3+a4x^4)',
8(1+2x)^3= a1+2a2x+3a3x^2+4a4x^3,
赋值 x = -1,则a1-2a2+3a3-4a4= -8
若(2x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0,则a0-a1+a2-a3+a4-a5=
若(2x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0,则ao-a1+a2-a3+a4-a5=
设(3x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0,求a5+a4+a3+a2+a1+a0的
已知(2x-1)^5=a0+a1x+a2x^2+a3x^3+a4x^4+a5x^5求a0+a1+a2+a3+a4+a5和
设(3x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0, 求a5+a4+a3+a2+a1的绝对
若(2x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0,则a0-a1+a2-a3+a4-a5=
已知(2x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0,则a1+a3+a5=__
已知(3x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x^1+a0,求a1+a3+a5
(2x-1)^6=a6x^6+a5x^5+a4x^4+a3x^3+a2x^2+a1x+1,则a6+a5+a4+a3+a2
(2x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0
(x+1)^4=a0+a1x+a2x^2+a3x^3+a4x^4,求a0+a1+a2+a3+a4的值.
(2x-1)^5=a5x^5+a4x^4+a3x^3+a2x^2+a1x+a0.