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化简[(xx-2xy+yy)(xx-2xy+yy)-xxxx+yyyy]÷(xx-yy)(xx-yy)的结果是

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化简[(xx-2xy+yy)(xx-2xy+yy)-xxxx+yyyy]÷(xx-yy)(xx-yy)的结果是
化简[(xx-2xy+yy)(xx-2xy+yy)-xxxx+yyyy]÷(xx-yy)(xx-yy)的结果是
原式=[(x-y)²(x-y)²-(x²+y²)(x²-y²)]/(x²-y²)²
=[(x²-2xy+y²)-(x²+y²)]/(x²-y²)
=-2xy/(x²-y²)