求解3^(log3根号3)+e^(ln(根号2/2))
(log3 2)+log9 2)*(log4 3+log8 3)+(log3 3^1/2)^2+ln根号e-lg1
求值.(log3^2+log9^3)*(log4^3+log8^3)+(log3^3^1/2)^2+ln根号下e-lg1
log2 5*log5 81*log3 4+ln根号e
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
设a=log3π,b=log3根号3,c=log3根号2比较abc
log2(根号3)和log3(根号2)哪个大有判断方法吗
(log2 5+log4 125)log3 2/ log根号3 5
(log3^4+log5^2)(log2^9+log2^根号3)
log3(2)=a,3^b=5,用a,b表示log3(根号30)
根号3+1-(3根号2-2根号3)(根号18+根号12)此题求解.
计算 lg3*log3^4+(lg5)^2-(lg2)^2+(根3-根2)^-1-根号下5-2倍根号6e^2分之1ln2
计算:1/(根号0.25)+(1/27)^-1/3+根号[(lg3)^2-lg9+1]-lg1/3+81^0.5log3