一道积分问题:∫sinh((lnx))sin((lnx))dx
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一道积分问题:∫sinh((lnx))sin((lnx))dx
如果不方便可以写在纸上再上传图片,一样可以接受,
如果不方便可以写在纸上再上传图片,一样可以接受,
![一道积分问题:∫sinh((lnx))sin((lnx))dx](/uploads/image/z/17955411-51-1.jpg?t=%E4%B8%80%E9%81%93%E7%A7%AF%E5%88%86%E9%97%AE%E9%A2%98%EF%BC%9A%E2%88%ABsinh%28%28lnx%29%29sin%28%28lnx%29%29dx)
Q: ∫sinh((lnx))sin((lnx)) dx
Let u = ln(x)
∴ du = (1/x) dx
Note that e^(u)sinh((lnx))
= e^(u) [ e^ln(x) - e^-ln(x) ] / 2
= e^(u)(e^(u) - e^(-u)) /2
= (1/2) (e^(2u) -1)
∫ sinh((lnx))sin((lnx)) dx
= ∫ e^(u)sin(u)sinh(u)du (add in e^u, so you can utilize above formula)
= ∫ (1/2)(e^(2u)-1)sin(u) du (substitute in above formula)
= 1/2 ∫ (e^(2u)sin(u) - sin(u))du
= 1/2 ∫ e^(2u)sin(u)du - 1/2 ∫ sin(u)du
You have two choices here:
1) Use integration by parts to solve the first integral, ∫ e^(2u)sin(u)du
2) Use the formula, ∫ e^(αu)sin(βu)du = e^(αu)(-β cos(βu) + αsin(βu)) / (α²+ β²)、
I chose the latter one.
= 1/5 e^(2u)sin(u) - 1/10 e^(2u)cos(u) - 1/2 ∫ sin(u) u
= 1/5 e^(2u)sin(u) - 1/10 e^(2u)cos(u) + cos(u)/2 + C
Now substitude u = ln(x) back into the equation.
= 1/5 x²sin(ln(x)) - 1/10 x²cos(ln(x)) + 1/2 cos(ln(x)) + C
= (1/10)(2x²sin(ln(x)) - (x²-5)cos(ln(x)) + C
∴ (1/10)(2x²sin(ln(x)) - (x²-5)cos(ln(x)) + C
Let u = ln(x)
∴ du = (1/x) dx
Note that e^(u)sinh((lnx))
= e^(u) [ e^ln(x) - e^-ln(x) ] / 2
= e^(u)(e^(u) - e^(-u)) /2
= (1/2) (e^(2u) -1)
∫ sinh((lnx))sin((lnx)) dx
= ∫ e^(u)sin(u)sinh(u)du (add in e^u, so you can utilize above formula)
= ∫ (1/2)(e^(2u)-1)sin(u) du (substitute in above formula)
= 1/2 ∫ (e^(2u)sin(u) - sin(u))du
= 1/2 ∫ e^(2u)sin(u)du - 1/2 ∫ sin(u)du
You have two choices here:
1) Use integration by parts to solve the first integral, ∫ e^(2u)sin(u)du
2) Use the formula, ∫ e^(αu)sin(βu)du = e^(αu)(-β cos(βu) + αsin(βu)) / (α²+ β²)、
I chose the latter one.
= 1/5 e^(2u)sin(u) - 1/10 e^(2u)cos(u) - 1/2 ∫ sin(u) u
= 1/5 e^(2u)sin(u) - 1/10 e^(2u)cos(u) + cos(u)/2 + C
Now substitude u = ln(x) back into the equation.
= 1/5 x²sin(ln(x)) - 1/10 x²cos(ln(x)) + 1/2 cos(ln(x)) + C
= (1/10)(2x²sin(ln(x)) - (x²-5)cos(ln(x)) + C
∴ (1/10)(2x²sin(ln(x)) - (x²-5)cos(ln(x)) + C