作业帮 > 综合 > 作业

求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)

来源:学生作业帮 编辑:搜狗做题网作业帮 分类:综合作业 时间:2024/07/11 14:47:47
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
=[2sin(π/11)cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)]/2sin(π/11)
=[sin(2π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)]/2sin(π/11)
=[sin(4π/11)cos(3π/11)cos(4π/11)cos(5π/11)]/4sin(π/11)
=[sin(8π/11)cos(3π/11)cos(5π/11)]/8sin(π/11)
=[sin(3π/11)cos(3π/11)cos(5π/11)]/8sin(π/11)
=[sin(6π/11)cos(5π/11)]/16sin(π/11)
=[sin(5π/11)cos(5π/11)]/16sin(π/11)
=sin(10π/11)]/32sin(π/11)
=1/32
关键在于知道如何使用sin2x=2SinxCosx.