y=sin(2x+1)+arctanx
证明sin(arctanx)=x/根号(1+x^2)
求通解(1+x^2)y'+y=arctanx
(1+x^2)y'=arctanx,求微分方程,
设f(x)可导,且f'(0=1,又y=f(x^2+sin^2x)+f(arctanx),求dy/dx /x=0
3.设y=(1+x^2)arctanx,求y" ,y"/x=1 .
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
y=(2x^3+x^1/2+4arctanx)/x求导数y''与y'
求函数y=1+x分之arctanx的导数,
tan(arctanX+arctanY)=(X+Y)/(1-XY)
求函数y=(x-1)*e^(∏/2+arctanx)的斜渐近线
求函数y=(x-1)e^(π/2+arctanx)的斜渐近线
y=(1+x∧2)arctanx二阶导数