三角函数最大值最小值的题
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三角函数最大值最小值的题
f(x)=sin(2x-π/6) 在区间[-π/6,5π/6]上的最大值和最小值 分别是 1 和-1 这错了吗`?
f(x)=sin(2x-π/6) 在区间[-π/6,5π/6]上的最大值和最小值 分别是 1 和-1 这错了吗`?
![三角函数最大值最小值的题](/uploads/image/z/17702956-28-6.jpg?t=%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E6%9C%80%E5%A4%A7%E5%80%BC%E6%9C%80%E5%B0%8F%E5%80%BC%E7%9A%84%E9%A2%98)
x belongs to [-pai/6,5pai/6],
so
2x-pai/6 belongs to [-pai/2,3pai/2]
draw the picture of this function
according to the picture,we can get that
f(x) belongs to [-1,1],
so
the maximum of the function is 1
the minimun of the function is -1
so
your answer is right
so
2x-pai/6 belongs to [-pai/2,3pai/2]
draw the picture of this function
according to the picture,we can get that
f(x) belongs to [-1,1],
so
the maximum of the function is 1
the minimun of the function is -1
so
your answer is right