(5m^2n^-2)^2*3m^-3n^3
(n-m)^3×(m-n)^2-(m-n)^5
因式分解(n-m)^3(m-n)^2-(m-n)^5
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
(m+5n)^2-2(5n+m)(n-3m)+(3m-n)^2
[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]
计算[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2
初一计算:(m+5n)(m-n)-6(m+2n)(n-3n)?
[5m(3m-n)+2n(n-3m)]/(3m-n)
计算:5(m+n)(m-n)-2(m+n)^2-3(m-n)^2
5(m+n)(m-n)-2(m+n)平方-3(m-n)平方
(m-5n)(m-n)-6(m+2n)(m-3n)
[(m-n)^2*(m-n)^3]^2/(m-n)^4