数列累乘法an/an-1=1-n/n+1 用累乘法求an通项 已知a1=1/2
已知数列{An}满足An+1=2(n+1)*5的n次方*An,A1=3,用累乘法求数列{An}的通项公式
累乘法求数列通项公式,an+1=2^n*an,a1=1
数列累乘法?已知数列an,a1=6,a(n+1)/an=(n+3)/n 求an通项公式
在数列(an)中,已知a1=3,nan=(1+n)*an+1求an.用累乘法解出来,
数列的通项公式的求法1.累加法已知数列{an}满足an+1=an+2n+1,a1=1,求an2.累乘法已知数列{an}满
数列累乘法计算:a1=1,Sn=n^2an(n≥2),求an,帮帮忙吧·····
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
已知数列an满足a1=1/2 sn=n平方×an 求an
已知数列{an},满足a1=1/2,Sn=n²×an,求an
已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an
已知数列{an}中a1=6,且an-an-1=(an-1/n)+n+1(n属于N*,n≥2),求an