化简(1+cos2x/sin2x)乘以(1+cosx/cosx)
化简:(sinx+sin2x)/(1+cosx+cos2x)
1.求最简形式:sin2x/(1+cos2x)*cosx/(1+cosx)*sinx/(1-cosx)
sin2x/(1+cos2x)*cosx/(1+cosx)*sinx/(1-cosx)
怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx
化简sin2x*tanx cos2x*1/tanx 2sinx*cosx
sin2X/(1+cosX+sinX)化简
求证:(1-2sinx×cosx)/cos2x-sin2x=(cos2x-sin2x)/(1+2sinx×cosx)
(1+cos2x)/2cosx=sin2x/(1-cos2x)
已知x∈(0,π),且sinx+cosx=1/2 求sin2x+cos2x,sinx-cosx的值
求lim(x→π/4) (sin2x-cos2x-1)/(cosx-sinx)的极限
sinx×cos2x-sin2x×cosx
已知sinx=-1/2cosx,cosx-sinx/cosx+sinx+sin2x+cos2x的值