化学反映如下:CH4(g)+co2(g)==2co(g)+2H2(g) △rGm=170.730kj/mol △rSm=
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化学反映如下:CH4(g)+co2(g)==2co(g)+2H2(g) △rGm=170.730kj/mol △rSm=256.712KJ/mol
问题在25° CH4(g),co2(g)分压均为150KP 2co(g)+2H2(g)分压均为50KP 求△rGm,△rSm
问题在25° CH4(g),co2(g)分压均为150KP 2co(g)+2H2(g)分压均为50KP 求△rGm,△rSm
![化学反映如下:CH4(g)+co2(g)==2co(g)+2H2(g) △rGm=170.730kj/mol △rSm=](/uploads/image/z/16847038-46-8.jpg?t=%E5%8C%96%E5%AD%A6%E5%8F%8D%E6%98%A0%E5%A6%82%E4%B8%8B%EF%BC%9ACH4%EF%BC%88g%29%2Bco2%28g%29%3D%3D2co%28g%29%2B2H2%28g%29+%E2%96%B3rGm%3D170.730kj%2Fmol+%E2%96%B3rSm%3D)
△Sm=-Rln(V2/V1)=Rln(p2/p1)=8.314×ln(100/300)=-9.134J/(mol.K)
△rGm=△rGm(标准)+T△Sm=170.730+298.15×(-9.134)/1000=168.007KJ/mol
△rSm=△rSm(标准)+△Sm=256.712+(-9.134)=247.578J/(mol.K)
PS:题目里的△rSm(标准)=256.712KJ/mol,单位错了,应该是J/(mol.K)
△rGm=△rGm(标准)+T△Sm=170.730+298.15×(-9.134)/1000=168.007KJ/mol
△rSm=△rSm(标准)+△Sm=256.712+(-9.134)=247.578J/(mol.K)
PS:题目里的△rSm(标准)=256.712KJ/mol,单位错了,应该是J/(mol.K)
已知2H2(g)+O2(g)==2H2O(l) △H=-571.6KJ/mol CH4(g)+2O2(g)==CO2(g
已知:2H2(g)+O2(g)=2H2O(l) △H=-571.6KJ/mol CH4(g)+2O2(g)=CO2(g)
已知2H2O(L)=2H2(g)+O2(g) △H=+571.6kJ/mol CH4(g)+2O2(g)=CO2(g)+
已知:CH4(g)+2O2(g)=CO2(g)+2H2O(l)△H=-890.3 KJ*mol-1H2(g)+0.5O2
已知CH4(g)+2O2(g)==CO2(g)+2H2O(l); △H=-890kJ/mol 现有CH4和CO的混合气体
(1)CH4(g)+2O2(g)=CO2(g)+2H2O(l),△H1=-890.3kj/mol
在一定条件下,CO和CH4燃烧的热化学方程式为:CO(g)+1/2O2=CO2(g);△H=-283KJ/mol
H2(g)+1/2O2(g)=H2O(l) 焓变= -282.8KJ/mol CO(g)+1/2O2(g)=CO2(g)
已知如下两个热化学方程式 C(s) O2(g)===CO2(g);△H=-393.5kJ/mol 2H2(g)
已知:2H2(g)+O2(g)═2H2O(l)△H=-571.6kJ•mol-1;CH4(g)+2O2(g)═CO2(g
已知下列两个化学方程式:2CO(g)+O2(g)=2CO2(g) △H=-563.6kJ/mol
求详解.已知CH4(g)+2O2(g)=CO2(g)+2H2O(l);ΔH=-890 kJ·mol-1,现有CH4和CO