已知函数f(x)=sin(x+π/6)+cos(x+π/3)+sinx+a(a属于R,且a为常数),若函数f(x)在[-
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已知函数f(x)=sin(x+π/6)+cos(x+π/3)+sinx+a(a属于R,且a为常数),若函数f(x)在[-π/2,π/2]上的最大值
与最小值和为2,求实数a的值
与最小值和为2,求实数a的值
![已知函数f(x)=sin(x+π/6)+cos(x+π/3)+sinx+a(a属于R,且a为常数),若函数f(x)在[-](/uploads/image/z/16790230-46-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dsin%EF%BC%88x%2B%CF%80%2F6%29%2Bcos%28x%2B%CF%80%2F3%29%2Bsinx%2Ba%28a%E5%B1%9E%E4%BA%8ER%2C%E4%B8%94a%E4%B8%BA%E5%B8%B8%E6%95%B0%29%2C%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%5B-)
f(x)=sin(x+π/6)+cos(x+π/3)+sinx+a
=sinx*cosπ/6+cosx*sinπ/6+cosx*cosπ/3-sinx*sinπ/3+sinx+a
=√3/2sinx+1/2cosx+1/2cosx-√3/2*sinx+sinx+a
=cosx+sinx+a
=√2sin(x+π/4)+a
f(x)在[-π/2,π/2]上的最大值1+a,最小值-1+a
(1+a)+(-1+a)=2
a=1
=sinx*cosπ/6+cosx*sinπ/6+cosx*cosπ/3-sinx*sinπ/3+sinx+a
=√3/2sinx+1/2cosx+1/2cosx-√3/2*sinx+sinx+a
=cosx+sinx+a
=√2sin(x+π/4)+a
f(x)在[-π/2,π/2]上的最大值1+a,最小值-1+a
(1+a)+(-1+a)=2
a=1
f(x)=sin(x+pai/6)+cos(x+pai/3)+sinx+a(a属于R+且a为常熟),并且函数f(x)的最
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