5c/6a^2b+7a/8b^2c-b/12a^2c
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
{A+2B-3C=4,5A-6B+7C=8}求代数式A:B:C 2A-3C/A+2B
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(
行列式证明|b+c c+a a+b| | a b c||a+b b+c c+a| = 2 |c a b||c+a a+b
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
计算(a-b)(a-c)/(a+b-2c)(a+c-2b)+(b-c)(b-a)/(b+c-2a)(b+a-2c)+(c
计算a(b+c-a)^2+b(c+a-b)^2+c(a+b-c)^2+(b+c-a)(c+a-b)(a+b-c)
化简:2a-b-c/(a-b)(a-c) + 2b-a-c/(b-c)(b-a) + 2c-a-b/(c-b)(c-a)
化简(2a-b-c)/(a+b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-b)(c-a
已知a+b/a-b=b+c/2(b-c)=c+a/3(c-a),求证:8a+9b+5c=0
(a+b)/(a-b)=(b+c)/2(b-c)=(c+a)/3(c-a),abc互不相等,证8a+9b+5c=o
初二分式的加减法2a-b-c/(a-b)(a-c)+ 2b-c-a/(b-c)(b-a)+ 2c-b-a/(c-b)(c