定积分f1/2到2(1+x-1/x)e^(x+1/x)dx?
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定积分f1/2到2(1+x-1/x)e^(x+1/x)dx?
![定积分f1/2到2(1+x-1/x)e^(x+1/x)dx?](/uploads/image/z/16619009-41-9.jpg?t=%E5%AE%9A%E7%A7%AF%E5%88%86f1%2F2%E5%88%B02%EF%BC%881%2Bx-1%2Fx%29e%5E%28x%2B1%2Fx%29dx%3F)
∫(1/2->2) (1+x-1/x)e^(x+1/x) dx
= ∫(1/2->2) e^(x+1/x) dx + ∫(1/2->2) (x-1/x)e^(x+1/x) dx,设K = ∫(1/2->2) (x-1/x)e^(x+1/x) dx
= x * e^(x+1/x) - ∫(1/2->2) x de^(x+1/x) + K 2) x * e^(x+1/x) * (1-1/x²) dx + K
= x * e^(x+1/x) - ∫(1/2->2) (x-1/x)e^(x+1/x) dx + K
= (2)e^(2+1/2) - (1/2)e^[(1/2)+1/(1/2)] - K + K
= (3/2)e^(5/2)
= ∫(1/2->2) e^(x+1/x) dx + ∫(1/2->2) (x-1/x)e^(x+1/x) dx,设K = ∫(1/2->2) (x-1/x)e^(x+1/x) dx
= x * e^(x+1/x) - ∫(1/2->2) x de^(x+1/x) + K 2) x * e^(x+1/x) * (1-1/x²) dx + K
= x * e^(x+1/x) - ∫(1/2->2) (x-1/x)e^(x+1/x) dx + K
= (2)e^(2+1/2) - (1/2)e^[(1/2)+1/(1/2)] - K + K
= (3/2)e^(5/2)