2x+y+z=4 x+2y+z=8 x+y+2z=24 求x,y,z
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知x+4y+z=24,2x+7y=2z=41,求x+y+z
已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值
若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值
已知X、Y、Z满足2X-Y+4Z=8(1);X-2Y-Z=7(2)求X-Y-Z的值
已知x,y,z满足2x-y+4z=8,x-2y-z=7,求x-y+z的值.要2种方法
已知:X、Y、Z满足2X-Y+4Z=8,X-2Y-Z=7,求X-Y+Z的值
已知x,y,z满足2x-y+4z=8,x-2y-z=7,求x-y+z的值.
已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值
1 已知想x,y,z满足2x-y+4z=8,x-2y-z=7,求x-y+z的值
2x+y+z=4 x+2y+z=8 x +y+2z=24