设等差数列{an}的前n项和为Sn,等差数列{bn}的前n项和为Tn,若Sn/Tn=3n+1/5n-2,则a4/b4=?

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设等差数列{an}的公差为a
等差数列{bn}的公差为b
S(2n-1)=［a1+a(2n-1)］*(2n-1)/2
=2an*(2n-1)/2
=(2n-1)an
T(2n-1)=［b1+b(2n-1］*(2n-1)/2
=2bn*(2n-1)/2
=(2n-1)bn
S(2n-1)/T(2n-1)=［(2n-1)an］/［(2n-1)bn］
=an/bn
a4/b4=S7/T7
=(3*7+1)/(5*7-2)
=22/33
=2/3

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