已知字母a ,b满足根号下a-1+根号下b-2=0求1/ab+1/(a+2)(b+2)+.1/(a+2008)(b+20
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已知字母a ,b满足根号下a-1+根号下b-2=0求1/ab+1/(a+2)(b+2)+.1/(a+2008)(b+2008)的值
1-1/2+1/2-1/3+1/3-1/4+.....+1/2009-1/2010
这一步怎么一下变成的减号啊
1-1/2+1/2-1/3+1/3-1/4+.....+1/2009-1/2010
这一步怎么一下变成的减号啊
![已知字母a ,b满足根号下a-1+根号下b-2=0求1/ab+1/(a+2)(b+2)+.1/(a+2008)(b+20](/uploads/image/z/15766095-39-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AD%97%E6%AF%8Da+%2Cb%E6%BB%A1%E8%B6%B3%E6%A0%B9%E5%8F%B7%E4%B8%8Ba-1%2B%E6%A0%B9%E5%8F%B7%E4%B8%8Bb-2%3D0%E6%B1%821%2Fab%2B1%2F%28a%2B2%29%28b%2B2%29%2B.1%2F%28a%2B2008%29%28b%2B20)
√(a-1)+√(b-2)=0
则a=1,b=2
1/1*2=1-1/2
1/2*3=1/2-1/3
1/3*4=1/3-1/4
.
1/2009*2010=1/2009-1/2010
1/ab+1/(a+2)(b+2)+.1/(a+2008)(b+2008)
=1/1*2+1/2*3+1/3*4+.+1/2009*2010
=1-1/2+1/2-1/3+1/3-1/4+.+1/2009-1/2010
=1-1/2010
=2009/2010
则a=1,b=2
1/1*2=1-1/2
1/2*3=1/2-1/3
1/3*4=1/3-1/4
.
1/2009*2010=1/2009-1/2010
1/ab+1/(a+2)(b+2)+.1/(a+2008)(b+2008)
=1/1*2+1/2*3+1/3*4+.+1/2009*2010
=1-1/2+1/2-1/3+1/3-1/4+.+1/2009-1/2010
=1-1/2010
=2009/2010
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