化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
log2(3)+log3(5)+log3(2)=?
(log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 ,
(log3^4+log5^2)(log2^9+log2^根号3)
(log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)=
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
log3(2)*log5(3)*log8(5)
[log2(3)+log4(9)][log3(4)+log9(2)]等于
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))